some math problems in C

[EvangelineBush33]

I want to calculate secant method using C language
That is a program—->

#include<stdio.h><br /> #include<math.h><br /> #include<stdlib.h><br /> main()<br /> {<br /> double fx(double x);<br /> double x0,x1,x2,f0,f1,f2,err;<br /> int n,i;<br /> printf("nn f(x) =x*x*x-5*x-7");<br /> printf("nnEnter an interval [x0,x1] in"<br /> " which root is to be found");<br /> printf("nx0 =");<br /> scanf("%f",&#038;x0); /* INTERVAL[x0,x1] is to be entered here */<br /> printf("x1=");<br /> scanf("%f",&#038;x1);<br /> printf("n Enter the number of iterations=");<br /> scanf("%d",&#038;n);<br /> printf("npress any key for display of iterations...n");<br /> getchar();<br /> i=0;<br /> while (n > 0)<br /> {<br /> f0=fx(x0);<br /> f1=fx(x1);<br /> x2 = x1-((x1-x0)/(f1-f0))*f1;<br /> i++;<br /> printf("n x[%d]=%f x[%d]=%f",i,i-1,x0,i,x1);<br /> printf("n f[%d]=%f f[%d]=%f",i,i-1,f0,i,f1);<br /> printf("n x[%d]=%f",i+1,x2);<br /> x0=x1;<br /> x1=x2;<br /> getchar();<br /> }<br /> printf("nnThe value of root is =%f",x2);<br /> }<br /> double fx(double x)<br /> {<br /> double f;<br /> f=x*x*x-5*x-7;<br /> return(f);<br /> }

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#include<stdio.h><br /> #include<math.h><br /> #include<stdlib.h><br /> main()<br /> {<br /> double fx(double x);<br /> double x0,x1,x2,f0,f1,f2,err;<br /> int n,i;<br /> printf("nn               f(x) =x*x*x-5*x-7");<br /> printf("nnEnter an interval [x0,x1] in"<br /> " which root is to be found");<br /> printf("nx0 =");<br /> scanf("%f",&#038;x0);   /* INTERVAL[x0,x1] is to be entered here   */<br /> printf("x1=");<br /> scanf("%f",&#038;x1);<br /> printf("n Enter the number of iterations=");<br /> scanf("%d",&#038;n);<br /> printf("npress any key for display of iterations...n");<br /> getchar();<br /> i=0;<br /> while (n > 0)<br /> {<br /> f0=fx(x0);<br /> f1=fx(x1);<br /> x2 = x1-((x1-x0)/(f1-f0))*f1;<br /> i++;<br /> printf("n      x[%d]=%f      x[%d]=%f",i,i-1,x0,i,x1);<br /> printf("n      f[%d]=%f       f[%d]=%f",i,i-1,f0,i,f1);<br /> printf("n                               x[%d]=%f",i+1,x2);<br /> x0=x1;<br /> x1=x2;<br /> getchar();<br /> }<br /> printf("nnThe value of root is =%f",x2);<br /> }<br /> double fx(double x)<br /> {<br /> double f;<br /> f=x*x*x-5*x-7;<br /> return(f);<br /> }

But while running not the erreo is displayed but the results displayed is
f(x) =x*x*x-5*x-7

Enter an interval [x0,x1] in which root is to be found
x0 =2.5
x1=3

Enter the number of iterations=4

press any key for display of iterations…

x[1]=0.000000 x[0]=0.000000
f[1]=-7.000000 f[0]=-7.000000
x[2]=inf

Means not able to calculate root as seen in the output it is x[1]=0…

so what will be the problem????

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