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[falguni1]

Hi all
My name is Vahid Majidi.
I am learning C++, and I will be glad if I can answer questions of those newcommers to C++, to help others learn more and learn from others.
Thanks

[bankkung]

Hello my community,

I am new to this forum & want to solve a project question.Ave tried my best but it is not executing, shows 8 errors. I am trying to find the prime numbers between 1 -7000.The sub intervals that holds themost  prime numbers and printing a histogram.

C

#include<stdio.h> #include<conio.h> void main() {  int num = 0;  prime_num(num); }  {   for(int i=0;i<=7000;i++)   {   for(int j=2; j <= 7000;j++)   {    if( i != j && 1 != j)    {     return 0;     break;    }    if(num%1 == num)     {     if (isprime)     {      printf("Prime:", i);    }     return 1;   }

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#include<stdio.h> #include<conio.h> void main() {  int num = 0;  prime_num(num); }  {   for(int i=0;i<=7000;i++)   {   for(int j=2; j <= 7000;j++)   {    if( i != j && 1 != j)    {     return 0;     break;    }    if(num%1 == num)     {     if (isprime)     {      printf("Prime:", i);    }     return 1;   }

• This reply was modified 9 years, 5 months ago by M. Saqib.
• This reply was modified 4 years, 9 months ago by M. Saqib.

[annalith]

hi my community give program.

• This reply was modified 9 years, 5 months ago by M. Saqib.
• This reply was modified 3 years, 9 months ago by M. Saqib.

[Jeevan M R]

Hi Mr. Vahid Majidi, 
I am Lalit Sharma and I have a query. 
Please help me to write a program in C++, How to count all the three digit number tht lie between 100 to 300 and whose 1st & last digit is 2.
If possible then please reply me at [email protected].
Hope to hear from you

[[email protected]]

How to count all the three digit number tht lie between 100 to 300 and whose 1st & last digit is 2?
Ans:

C

#include <iostream> using namespace std; void display() {  int count = 0;  for(int i = 100;i<300;i++)  {   int value = i;   if(((value%10)== 2) &&(value/100)==2)   {    cout<<value<<endl;    count++;   }  }  cout<<"Total Number "<<count<<endl; } void main() {  display(); } output: 202 212 222 232 242 252 262 272 282 292 Total Number 10

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#include <iostream> using namespace std; void display() {  int count = 0;  for(int i = 100;i<300;i++)  {   int value = i;   if(((value%10)== 2) &&(value/100)==2)   {    cout<<value<<endl;    count++;   }  }  cout<<"Total Number "<<count<<endl; } void main() {  display(); }   output: 202 212 222 232 242 252 262 272 282 292 Total Number 10

• This reply was modified 9 years, 5 months ago by M. Saqib.
• This reply was modified 4 years, 9 months ago by M. Saqib.
• This reply was modified 4 years, 9 months ago by M. Saqib.
• This reply was modified 4 years, 9 months ago by M. Saqib.

[S.Thananchayan]

Thats awsome I was thinking about this one.
This is the way I was going-
 

C

#include <iostream> #include <algorithm> #include <vector> bool IsThis (int x) { return (x=1);  } bool IsAnswer (int i) { return (((i%10)==2)&(i/100)==2); } int main () {   int mynumbers;   int mycount;   std::vector<int> myscope;   for (int x =100; x<300; x++) myscope.push_back(x);   std::vector<int> myvector;   for (int i=100; i<300; i++) myvector.push_back(i);     mynumbers = (int) count_if (myscope.begin(), myscope.end(), IsThis);    std::cout << "myvector contains " << mynumbers  << " numbers between 100 and 300.n";   mycount = (int) count_if (myvector.begin(), myvector.end(), IsAnswer);    std::cout << "myvector contains " << mycount  << " numbers that begin and end with 2.n";   return 0; }

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#include <iostream> #include <algorithm> #include <vector>   bool IsThis (int x) { return (x=1);  } bool IsAnswer (int i) { return (((i%10)==2)&(i/100)==2); } int main () {   int mynumbers;   int mycount;     std::vector<int> myscope;   for (int x =100; x<300; x++) myscope.push_back(x);   std::vector<int> myvector;   for (int i=100; i<300; i++) myvector.push_back(i);     mynumbers = (int) count_if (myscope.begin(), myscope.end(), IsThis);    std::cout << "myvector contains " << mynumbers  << " numbers between 100 and 300.n";     mycount = (int) count_if (myvector.begin(), myvector.end(), IsAnswer);    std::cout << "myvector contains " << mycount  << " numbers that begin and end with 2.n";   return 0; }

• This reply was modified 9 years, 5 months ago by M. Saqib.
• This reply was modified 4 years, 9 months ago by M. Saqib.
• This reply was modified 4 years, 9 months ago by M. Saqib.

[Jeevan M R]

Hi Arun,
I thank you very much for my problem solving.
Dear Arun, I have not executed this program but I’ll try it today.
Anyway many thanks once again.
 
Thanks & Regards,
Lalit Sharma
 
“Knowledge speaks & Wisdom listens”.

[Jeevan M R]

Hi mr_rich,
I thank you very much for my problem solving.
Dear friend, I have not executed this program but I’ll try it today.
Anyway many thanks once again.
Thanks & Regards,
Lalit Sharma
 
“Knowledge speaks & Wisdom listens”.

[Author]

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