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July 31, 2007 at 5:11 am in reply to: Welcome C++ #3203

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How to count all the three digit number tht lie between 100 to 300 and whose 1st & last digit is 2?
Ans:

#include <iostream>
using namespace std;
void display()
{
 int count = 0;
 for(int i = 100;i<300;i++)
 {
  int value = i;
  if(((value%10)== 2) &&(value/100)==2)
  {
   cout<<value<<endl;
   count++;
  }
 }
 cout<<"Total Number "<<count<<endl;
}
void main()
{
 display();
}

output:
202
212
222
232
242
252
262
272
282
292
Total Number 10

#include <iostream>

using namespace std;

void display()

{

int count = 0;

for(int i = 100;i<300;i++)

{

int value = i;

if(((value%10)== 2) &&(value/100)==2)

{

cout<<value<<endl;

count++;

}

cout<<"Total Number "<<count<<endl;

}

void main()

{

display();

}

output:

202

212

222

232

242

252

262

272

282

292

Total Number 10

This reply was modified 9 years, 6 months ago by M. Saqib.
This reply was modified 4 years, 10 months ago by M. Saqib.
This reply was modified 4 years, 10 months ago by M. Saqib.
This reply was modified 4 years, 10 months ago by M. Saqib.

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